TCS
Company
Numerical Ability
Number System
1*1!+2*2!+3*3!................2012*2012!= ?
Read Solution (Total 3)
-
- 1(1!)=1=2!-1=1
1(1!)+2(2!)=5=3!-1=5
1(1!)+2(2!)+3(3!)=23=4!-1=23
Similarly,1(1!)+2(2!)+3(3!)+................ +2012(2012!)=2013!-1
Answer is 2013!-1 - 9 years agoHelpfull: Yes(30) No(0)
- 1(1!)+2(2!)+3(3!)+...+n(n!)= (n+1)!-1 for all positive integers n.
(2012+1)!-1=2013!-1 - 9 years agoHelpfull: Yes(8) No(0)
- 1*1!+2*2!+3*3!=1+4+18
=23
=4!-1=(n+1)!-1
so for the above problem,
2013!-1 - 9 years agoHelpfull: Yes(2) No(0)
TCS Other Question