Hare in the other. The hare starts after the tortoise has covered 1/5 of its distance and that too leisurely3. A hare and a tortoise have a race along a circle of 100 yards diameter. The tortoise goes in one direction and the. The hare and tortoise meet when the hare has covered only 1/8 of the distance. By what factor should the hare increase its speed so as to tie the race?

• 40-5=35
  35-8=27
  35*27/25=37.8
• 9 years agoHelpfull: Yes(8) No(1)
• After tortoise covers 1/5th distance hare starts the race
  When hare covers 1/8th of distance tortoise meets hare
  So distance covered by tortoise = 1-(1/5 + 1/8)
  = 27/40
  Time taken by both is same
  time = dist/speed
  So (dist/ speed) of tortoise = (dist / speed) of hare
  let speed of tortoise be t and of hare be h
  27/40t = 1/8h
  h = (40/(8*27) )* t = 5/27 * t
  Now for the next part hare has to cover 7/8 th distance when tortoise covers 1/8 th distance
  so we get
  1/8t = 7/8h
  h = 7t
  so the factor by which h's speed increases = 7t/ (5/27 * t)
  which we get as 37.8
• 9 years agoHelpfull: Yes(4) No(0)
• let ,speed of hare be Vh and tortoise be Vt
  initially,
  Vh:Vt=25:(100pi-20pi-12.5pi)
  but to Tie the race ratio should be,
  Vh:Vt=125:25=5:1
  so 25x/(100pi-20pi-12.5pi)=5/1;
  x=42.39 ans
  
• 9 years agoHelpfull: Yes(1) No(2)
• 
  
  first distance = 1/x
  second distance = 1/y
  
  let z = xy-x
  required factor will be = z*(z-y)/x^2
  
  in this question..
  x=5 , y=8
  z=5*8-5=35
  z-y = 35-8 = 27
  required factor = 35*27/25 = 37.8 ans
• 9 years agoHelpfull: Yes(1) No(0)
• Total circumfrance = pie*diameter
  tortoise has covered = 25pie
  remaining distance = 75 pie
  1/8th of total distance = 12.5 pie
  let the velocity of tortoise = u and that of hare =v
  on time comparison we get
  62.5 pie/u = 12.5 pie/v
  5v=u so v=u/5
  
  now for remaining journey time taken by tortoise = 12.5 pie/u
  so velocity of hare to make a tie = 7*12.5 pie u / 12.5 pie
  =7u
  so 7u/u/5 = 35 times answer
  
• 9 years agoHelpfull: Yes(0) No(3)
• @diva plz explain
  So distance covered by tortoise = 1-(1/5 + 1/8)????
  
• 8 years agoHelpfull: Yes(0) No(0)