302th of 1st year is saturday. What is the 15th day of 5th Year ?

• 302 th of 1st year is saturday.so ending day in first year is also saturaday.(365-302=63 no of odd day is 0.so ending day also saturday.) therefore 2nd year 1st day is sunday.similarly 3rd year and 4th year is monday and tuesday.5th year starting day is thursday because 4th year is leap year.therefoe 15 of 5th year is friday.
• 9 years agoHelpfull: Yes(15) No(7)
• ans: thursday
  1st year remaining days: 365-302= 63 + 1 (including 302nd day)= 64 days
  2nd year= 365 days
  3rd year= 365 days
  4th year= 366 days (leap year)
  5th year= 15 days
  so total days = 64+365+365+366+15= 1175 days
  now 1175/7= 167 weeks and 6 days
  so 6th day starting from saturday is thursday.
  
• 9 years agoHelpfull: Yes(8) No(0)
• 63 +15+3+1(leap)/7=5 odd
  ... thursday
• 9 years agoHelpfull: Yes(6) No(1)
• 302 day in a year means OCT 29 (if its not a leap year) so in the year 2011 OCT 29th was Saturday (which is given in our question ) after 5 years i.e., 2015 -15th day is Thursday (according to our calender)
• 9 years agoHelpfull: Yes(3) No(0)
• 365-302=63
  last day of 1st year is saturday . 2nd year first day=sunday
  3rd year first day =monday
  4th year first day =tuesday
  5th year (followed by leap year who having 2 odd days at end )= thrusday
  15/7= 1 . now remainder 1 for thrusday is friday
  hence Friday is correct
• 9 years agoHelpfull: Yes(3) No(5)
• anyone explain the above question...
• 9 years agoHelpfull: Yes(1) No(0)
• is it necessary to submit the verbal ability section ?
  
• 9 years agoHelpfull: Yes(1) No(0)
• 302 th of 1st year is saturday.so ending day in first year is also saturaday.(no of odd day is 0.so ending day also saturday.) therefore 2nd year 1st day is sunday.similarly 3rd year and 4th year is monday and tuesday.5th year starting day is wednesday and because 4th year is leap year.therefoe 15 of 5th year is wednesday
  365-302=63/7= 0 odd days last day = saturaday
  2nd year 1st day sunday
  3rd year 1 st day monday
  4th year 1 st day tuesday
  5th year 1st day wednesday and 15th day also wednesday
• 9 years agoHelpfull: Yes(0) No(3)
• 1st year no of odd days= 0 ( simple divide by 7 and get remainder)
  2nd yr= 1(remember normal year has 1 odd day )
  3rd yr= 1
  4th yr =2 (remember leap year has 2 odd days)
  5th yr =1 (divide by 7)
  
  Total =5
  Then count from saturday. Its thursday = sat dy +5
• 7 years agoHelpfull: Yes(0) No(0)