1,5,6 ,25, 26,30,31, 125,126,
130,131,150,151,155,156,……… What
is the value of 33rd term in the
given series

• ans : 3126
  sol: 1st terms gives 2nd and 3rd terms
  1st term is 1
  2nd term 1*5=5 3rd term= 5+1=6
  similarly,
  4th term =5*5=25 5th term=25+1=26
  1st term gives 2nd and 3rd values
  2nd term gives 4th and 5th values
  lke wise
  16th term gives 32nd and 33rd values
  16 th term is 125*5=625
  32nd term is 625*5=3125 and 33rd value is 3126
• 9 years agoHelpfull: Yes(23) No(2)
• 3126..the series goes like..5*5=25 which comes after 1 place in between..6*5=30 which comes after two places in between...25*5=125..comes after 3 places in between.. and so on..also..after uliplying a number by 5..the number next to it also comes in the series..if my calculation is correct..the 33rd term should be 3126
• 9 years agoHelpfull: Yes(4) No(3)
• the series will like this,,,1,5,6 ,25, 26,30,31, 125,126,
  130,131,150,151,155,156,
  the logic like this--1,5,6,5*5=25 25+1=26 25+5=30 30+1=31
  25*5=125 125+1=126 125+5=130 130+1=131
  30*5=150 150+1=151 150+5=155 155+1=156
  125*5=625 625+1=626 625+5=630 630+1=631
  130*5=650 650+1=651 650+5=655 655+1=656......as it is all terms can calculated
  
  …625,626,630,631,650,651,655,656,750,751,755,756,775,776,780,781,3125,3126,3130,3131....so the 33rd terms ANS.- 3126
• 9 years agoHelpfull: Yes(4) No(0)
• 33 term in the series is 501.the series is as follows
  250,251,255,256,275,276,280,281,375,376,380,381,400,401,405,406,500.501.505,506
• 9 years agoHelpfull: Yes(3) No(4)
• answer is 501. Because the difference between the numbers pattern goes like this,
  4, 1, 19, 1 4, 1, 94, 1 4, 1, 19, 1 4, 1, 94, 1
• 9 years agoHelpfull: Yes(3) No(3)
• Here first two numbers 1,5 acts as the major subjects of the series. The key is the term in even place should be a multiple of 5 and the next term in odd place should be increased by 1.
  So leaving 1 and 5, the third term 6 = 5+1, 4th term = 5*5, 5th term = (5*5)+1, 6th term = 5*6, 7th term = (5*6)+1.... 14th term = 155 = 5*31,15th term = (5*31)+1 . from the series given, 31 is 7th term.So 16th term =5*125, 17th term = 5*126 ....... 30th term = 5*(15th term) = 5*156 ,32nd term = 5*(16th term) = 5*625 = 3125. So 33rd term = (32nd term)+1=3126.
• 9 years agoHelpfull: Yes(2) No(2)
• take the the all terms as t1,t2,t3,t4,t5,..........upto t15.
  by observing the given series we come to know that t2=t1*t1=1*5=5 &t3=t2+1
  next t4=t2*t2=5*5=25 & t5=t4+1=25+1=26
  t6=t2*t3=5*6=30 & t7=t6+1=30+1=31
  like wise t33=t32+1 & t32=t2*t16 but t16=t2*t8=5*125=625.
  hence=t32=t2*t16=5*625=3125 & t33=t32+1=3125+1=3126.
• 9 years agoHelpfull: Yes(2) No(0)
• ans is 3126
• 9 years agoHelpfull: Yes(1) No(1)
• thank u very much
• 9 years agoHelpfull: Yes(1) No(0)
• 1*5=5, 5+1=6, 6*5=30, 30+1=31, ....... and so on.. 33rd term is 625*5=3125, 3125+1=3126
• 9 years agoHelpfull: Yes(0) No(2)
• here these series is starting from 1 and then multiply it with 5 becomes second term and addition of 1 in that answer becomes third term so in this series 1,5,6.... and so on. Same for second term 5 produce 25 and 26 and so on ....
  So series becomes
  (n * 5)= X= second term
  (n * 5 ) + 1= X + 1 =Third term
  where n starts from 1 to next term of series and get continued from every previous answered...
• 9 years agoHelpfull: Yes(0) No(0)
• can anyone briefly explain after this step 4th term =5*5=25 5th term=25+1=26 what will be the pattern of the term N which is to be multiplied i mean for 2nd term 5 is multiplied with 1 & for 4th term 5 is multiplied with 5 for next term a/c to question given it should be multiplied with 25 but my doubt is i dint understand the relation for the number N multiplied with 5 for each term..
• 9 years agoHelpfull: Yes(0) No(0)