A team has won 80% of the games it has played in this season. In the next season it won 3 out of 5 matches and its losing percentage was 25%, how many matches the team has played in total?

• Let the total number of matches played be x
  No of matches played in prev season = (x-5)
  No of matches lost prev season = .2(x-5)--->20 percent
  No of matches lost this season =5-3=2
  We have been given loss percent as 25
  So
  .2*(x-5) + 2 = .25*x
  Solving, x=20
• 12 years agoHelpfull: Yes(35) No(1)
• answer is 20 matches .
  15 in 1st season and 5 then
  and win 12 in 1st season and 3 now
  so lost percentage is 25%
• 12 years agoHelpfull: Yes(10) No(4)
• 0.8x+3=0.75x+3.75
  x=15
  total match =x+5=20
• 12 years agoHelpfull: Yes(6) No(3)
• x*20/100+2=x*25/100
  solve x=20
  20+5=25
  
• 12 years agoHelpfull: Yes(2) No(6)
• how can u xactly say that it is 20.. it can be 40 also and any equation satisfing x=3y where x is the matches in 1st season and y is in second
• 12 years agoHelpfull: Yes(1) No(7)