We have an equal arms two pan balance and need
to weigh objects with integral weights in the range 1
to 40 kilo grams. We have a set of standard weights
and can place the weights in any pan. (i.e) some
weights can be in a pan with objects and some
weights can be in the other pan. The minimum number
of standard weights required is:
a) 4 b) 5
c) 6 d) 10

• option a
  that is 4
  and the required standard weights are 1, 3, 9, 27
  
  
• 9 years agoHelpfull: Yes(13) No(0)
• ans=4, Three std weights of 2 kg each and one std wt. of 5 kg
  
  We just need to factorize the magnitude of the highest weight, i.e., 40.
  
  40 = 2x2x2x5
  
  to weigh 1kg → 2x2 kg in one pan and 5 on the other
  
  to weigh 3 kgs → 2 kg in one pan and 5 kg on the other, and so on.
• 9 years agoHelpfull: Yes(6) No(1)
• ans is 6
  1,2,4,8,16,32
  
• 9 years agoHelpfull: Yes(2) No(2)
• 6( 4 1kg weight and 1 500 gm and 1 250 gm )
• 9 years agoHelpfull: Yes(1) No(4)
• Answer is option (a)
  try by keeping either of the weights on the two pans (1,3,9, and 27 )
  such that u get all the weights measured betweeen 1-40
  eg: for measuring 15 kg i would place 27 kg on one pan and (9,3=12kg) on the other such that the net weight=27-9-3=15kg
• 9 years agoHelpfull: Yes(1) No(0)
• i am confused which one is correct
  i think option c
• 9 years agoHelpfull: Yes(0) No(1)
• Plz explain Vinit how u got the answer? Thanks in advance.
• 9 years agoHelpfull: Yes(0) No(0)
• batao kassa kiya hai .Please
  
• 9 years agoHelpfull: Yes(0) No(0)
• Ans is a) 4 , and standard weight required are 1,2,5,10 kg weight each
• 9 years agoHelpfull: Yes(0) No(0)
• 1,2,5,10,20,50
• 9 years agoHelpfull: Yes(0) No(0)