Pls explain its answer with reason 1941 3483 1961 4181 find out the last 2 digits

I think , the two last digit should be 02.
Because the last digit is 1 in case of both numbers.
so, any power of 1 leads to 1.

for second digit :
In case of 1st number it is 4, any odd power of 4 leads to 4.
In case of 2nd number it is 6, any odd/even power of 6 leads to 6.

when last 2 digit are added ,the result will be like this 102.
so, last 2 digit is 02.
12 years agoHelpfull: Yes(19) No(17)
82
unit digit 1
tens digit 3*4=12
so 1st case no 121
similarly 2nd case
unit digit 1
ten digit 6*1=6
so number is 61
after adding the two no=(61+21)=82 (ans)
12 years agoHelpfull: Yes(18) No(4)
ans is 82....
12 years agoHelpfull: Yes(10) No(2)
82 is the ans.
12 years agoHelpfull: Yes(5) No(0)
ans is 02
12 years agoHelpfull: Yes(2) No(6)
explain how it was solve abhishek .plz........... i can't understand.
12 years agoHelpfull: Yes(1) No(0)
Rakesh Kumar :thanks ok...i get ur logic....u sure that is the correct answer?

n pls ,those who have posted 82 as their answers pls xplain how it comes
12 years agoHelpfull: Yes(1) No(1)
answer is 02 or 82.. plz clearify !
12 years agoHelpfull: Yes(1) No(0)
ye qstn kaunsa clg me tcs ka hai??
12 years agoHelpfull: Yes(0) No(2)
dnt knw egertrjut
12 years agoHelpfull: Yes(0) No(1)

Pls explain its answer with reason..

1941^3483 + 1961^4181= find out the last 2 digits