In box of balls, 2/3rd are blue and the remaining is pink. If 5/9 th of blue and 7/8 th of pink are defective, find the probability of picking up a defective ball, if there is a total of 146 balls in the box.

• Total ball=146
  picking a defective balls in 146= (146c1)=146
  probability of picking 1 defective blue or pink ball
  =(146*((2/3*5/9)+(1/3*7/8)))/146
  =10/27+7/24
  =143/216
• 12 years agoHelpfull: Yes(39) No(1)
• Ans 143/216
  Defective blue balls=146*(2/3)(5/9)=146*10/27
  Defective pink balls=146*(1/3)(7/8)=146*7/24
  Total defective balls=146(10/27 + 7/24)=146*143/216
  If 1 ball is to be picked from 146,then probability=(146*143)/(216*146)=143/216
  
• 12 years agoHelpfull: Yes(15) No(9)
• Let total balls are x
  Total Defective blue balls are (5/9)(2/3)*x=(10/27)x
  Total Defective pink balls are (1/3)(7/8)*x=(1/24)x
  
  So total defective balls' probability=
  
  (1/24 + 10/27) x
  ------------------ = 0.6620370=(143/216)
  x
  
• 12 years agoHelpfull: Yes(6) No(1)
• mi mokalu chuskondi ra...........jaffa
  
• 9 years agoHelpfull: Yes(0) No(0)