If I walk at 3 Km/hr i miss the train by 2 min. If however i walk at 4km/hr i reach 2min before the arrival of the train. How far do i walk to reach the station?

• difference in time will 2+2=4 min ,
  which is equal to 4/60=1/15hr
  therefore
  dis/3km/hr - dis/4km/hr =1/15,
  dis=4/5km
  which is equal to 800 m. (answer)
• 9 years agoHelpfull: Yes(22) No(0)
• Ans= 800 m
  3km/hr= 3/60 km/min
  3/60=d/(t+2)...............(1)
  4/60=d/(t-2)................(2)
  eq 1
  t= 20d-2;
  eq2
  d=4/5 km
  =800 m
  
  
• 9 years agoHelpfull: Yes(12) No(0)
• time diffrence = d/3-d/4 = 4/60mins.. thus d=4/5=0.8km
• 9 years agoHelpfull: Yes(6) No(0)
• let the required distance be x km.
  difference in time taken at two speeds= 2min+ 2min = 4min =4/60 =1/15 hours;
  
  so, x/3-x/4=1/15;
  solving dis we get the value of x=4/5 km or 800m
• 9 years agoHelpfull: Yes(5) No(1)
• ((product of speed )/(difference of speed) ) *(sum of T/60)
  
  ((3*4)/1))*(2+2)/60
  =4/5Km
• 9 years agoHelpfull: Yes(2) No(0)
• let require distance be x
  x/3-x/4=(2+2)/60=4/60=1/15
  4*x-3*x=12/15=4/5
  x= 800 mts
  
• 9 years agoHelpfull: Yes(1) No(0)
• Direct formula : required distance= {(product of two speeds)/difference in speed } * difference in time between arrival times .......i.e.,
  ((3*4)/1}4/60 [we have to put all in same units]
  Ans: 0.8km==800meters
• 9 years agoHelpfull: Yes(1) No(0)
• theres some error as if we solve in ths way it is coming.
  
  difference in time will 2+2=4 min ,which is equal to 4/60=1/15hr
  therefore dis/3-dis/4=1/15,
  dis=4/5.
• 9 years agoHelpfull: Yes(0) No(2)
• Ans is 5/2
  but dont know how?
• 9 years agoHelpfull: Yes(0) No(0)
• convert km/hr to m/s
  3*5/18=5/6 and 4*5/18=10/9
  difference in time is 4min so time=distance/speed take distance=x m
  6*x/5-9*x/10=4 so x=40/3m
• 9 years agoHelpfull: Yes(0) No(2)
• D=(s1*s2/speed gap)*time gap
  D=(3*4/1)4/60=4/5km
• 9 years agoHelpfull: Yes(0) No(0)
• Ans. is 266.6 m
• 9 years agoHelpfull: Yes(0) No(1)
• let the distance is x km.
  the differnce in time is 2+2=4
  so x/3-x/4=4/60
  x=4/5km
  x=800
• 9 years agoHelpfull: Yes(0) No(0)
• 3(x+2)=4(x-2)
  x=14 actual time
  thus the person reaches in x+2 = 16min
  16min=16/60 hr
  hence distance =3*(16/60)
  distance=4/5km=0.8km
• 9 years agoHelpfull: Yes(0) No(0)
• let distance=d
  time diffrence = d/3-d/4 = 4/60mins.. thus d=4/5=0.8km
  
• 9 years agoHelpfull: Yes(0) No(0)