(68-a)(68-b)(68-c)(68-d)(68-e)=725 then a+b+c+d= ?

• 725=5*5*29
  (68-39)*(68-63)*(68-63)*(68-67)*(68-67)=725
  a+b+c+d=39+63+63+67=232 (ans)
• 9 years agoHelpfull: Yes(17) No(2)
• 1st take Lcm of 725=5*5*29
  now make product as 5*5*29
  i.e. (68-39)=29,(68-63)=5,(68-63)=5,(68-67)=1,(68-67)=1.
  now a=39,b=63,c=63,d=67
  a+b+c+d=232
  there is no need of e.
  ans=232
• 9 years agoHelpfull: Yes(8) No(0)
• 1st take Lcm of 725=5*5*29
  we need a distinct five digit number so convert
  Lcm of 725=5*-5*29*-1*1
  (68-39)=29
  (68-63)=5
  (68-67)=1
  (68-69)=-1
  (68-73)=-5
  now,
  a=39,b=63,c=69,d=67,e=73
  so,
  39+63+69+67=238
• 9 years agoHelpfull: Yes(4) No(3)
• not possible
• 9 years agoHelpfull: Yes(0) No(1)