V 50 W
196 x y
269 z 123
if the sum of no in each row ,column, siagonal are same then find the value of (y+z).

• y+z=1122
  We can have eqn. 196+269+v=123+x+v ->x=342
  Also 269+196+v=50+v+w -> w=415
  Substituting values of x & w, we have sum of one diagonal=269+342+415=1026
  So Other values we get as v=561, y=488, z=634
  Therefore sum (y+z)=488+634=1122
  
• 12 years agoHelpfull: Yes(11) No(0)
• 269+123+z=50+x+z.....x=342
  w+y+123=196+x+y....w=415
  269+x+w=1026
  269+z+123=1026....z=634
  w+y+123=1026.....y=488
  y+z=1122
• 12 years agoHelpfull: Yes(6) No(0)