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Given is 54 + 51 + 48 + ... till n terms = 513. How many values of ‘n’ are possible?

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s=n/2[2a+(n-1)d]
d=-3,s=513
puting these value we get n=19,18
12 years agoHelpfull: Yes(24) No(0)

54+51+48+.........+0
this would be the series 19 th term is 0 (tn=a+(n-1)d)
s19=19(54+0)2=513
so n=19
12 years agoHelpfull: Yes(9) No(0)
54+(n-1)3=513
151
12 years agoHelpfull: Yes(1) No(8)

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