Two circles of radii 5 cm and 3 cm touch each other at A and also touch a line at B and C. The distance BC in cms is?
a. 60−−√
b. 62−−√
c. 68−−√
d. 64−−√

• Ans is sqrt(60)
  explenation:-
  Sqrt(D^2-(R-r)^2)
  D=R+r
  =5+3
  =8
  i.e sqrt{(8^2)-(5-3)^2}
  sqrt(60)
• 9 years agoHelpfull: Yes(9) No(0)
• Option A
  d2−(r1−r2)2
  
  82^2-(5-3)^2=sqrt(60)
  
  d = distance between centers
• 9 years agoHelpfull: Yes(2) No(1)
• 2 identical circles intersect so that their centre and point at which they intersect form a square of 1 cm.the area of portion that is common two circles is
  π2-1
  4
  √2-1
  √5
• 9 years agoHelpfull: Yes(1) No(4)
• diff b/w the radius is (5-3)=2
  so the distance b/w two contact points id
  sqrt{(R+r}^2-(R-r)^2}
  =sqrt(8^2-4^2)
  =sqrt(60)
• 9 years agoHelpfull: Yes(1) No(0)
• can you plz explain ABHISHEK KUMAR???
• 9 years agoHelpfull: Yes(0) No(2)
• explain please..
• 9 years agoHelpfull: Yes(0) No(0)
• how 82 taken distance between two center can u explain plz?
• 9 years agoHelpfull: Yes(0) No(0)
• (a).root 60
• 9 years agoHelpfull: Yes(0) No(0)