A car is 250 meters behind the bus. The car and bus are moving with speed 60 km/hr and 35 km/hr respectively. The car will be ahead of bus by 250 meters in:

• Ans 72 sec.
  Relative speed=60-35=25 Km/hr
  For car to be ahead of bus by 250 meter,distance to be covered=250+250=500m=0.5km
  So time taken=0.5/25=1/50 Hr or 3600/50=72 seconds
  
• 11 years agoHelpfull: Yes(63) No(5)
• total distance car should be car is 500m(because 250m behind of bus+250m ahead of bus). so,relative speed between car and bus is 60-35=25km/hr.25*5/18=125/18.
  t=(500*18)/125=72 seconds.
• 11 years agoHelpfull: Yes(14) No(2)
• Relative speed of the car(s)= 60km/hr-35km/hr= 25km/hr
  distance to be travelled(d)= 250+250= 500m= (1/2)km
  time taken= d/s= 1/(2*25)= 1/50hr= 60/50min=1min 12sec
  
• 11 years agoHelpfull: Yes(12) No(5)
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• 11 years agoHelpfull: Yes(12) No(8)
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• 11 years agoHelpfull: Yes(3) No(5)
• total distance=250+250=500m=.5km
  average speed=60-35=25km
  time=.5/25=1/50hour
  3600/50=72sec
• 11 years agoHelpfull: Yes(1) No(0)
• relative speed=(65-35)=25 km/hr
  25*1000 per 3600=125 meter per 18 sec
  so,t=250*18/125=36 sec
  as in 36 sec car and bus will be side by side....
  so,in 37 sec car will be ahead of bus by 250 meter
  
  
  
• 8 years agoHelpfull: Yes(1) No(0)
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• 11 years agoHelpfull: Yes(0) No(0)
• (x+0.5)/60 =x/35
  t=x/35
  anss will be 72 sec
• 11 years agoHelpfull: Yes(0) No(0)
• 72 sec thanks
• 8 years agoHelpfull: Yes(0) No(0)
• after 20 hrs......
  let the time will be T then 60T=35t+500..then T=500/25=20 hrs........
• 8 years agoHelpfull: Yes(0) No(6)
• time taken by car to just cross bus 250m apart= 250/(125/18) = 36sec......(i converted km/hr to m/sec)
  now to gain another 250m ,car will take 36*s= 72sec
• 8 years agoHelpfull: Yes(0) No(0)
• time taken by car to just cross bus 250m apart= 250/(125/18) = 36sec......(i converted km/hr to m/sec)
  now to gain another 250m ,car will take 36*2= 72sec
• 8 years agoHelpfull: Yes(0) No(1)
• 72 seconds
• 4 years agoHelpfull: Yes(0) No(0)