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a and b starts from their house at 10am. they travek from their house on MG road at 20kmph and 40kmph. they meet at T junction at 12:00 pm B reaches the T junction earlier and turns right .Both of them continue travelling till 2:00pm what is distance between a& b at 2:00pm?
Read Solution (Total 21)
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- a reaches the junction at 12 after travelling 40 km
but b reaches junction at 11 after travelling 40 km.
at 2 am. a will travel 40 km from junction
at 2 am. b will travel for 3 hrs that is 120 km from junction so it travel 10 km.
distance between them is 120 +40=160 km
- 12 years agoHelpfull: Yes(62) No(14)
- It is given that at 12:00 pm , they meet at T junction.
After that they travel for 2 hours.
Here, 2 conditions arises.....
1st condition : Both A & B travel in same direction.
2nd condition : Both A & B travel in different direction.
According to 1st condition,
The distance between A & B = 80-40=40 km
According to 2nd condition,
The distance between A & B =80+40=120 - 12 years agoHelpfull: Yes(30) No(20)
- @rakesh kumar
but after reachd at junction B turns right while A not
so i thnk A'll go straight and cover distance 20*2=40 km
and B turns right and cover 80 km
so acc to me distance should be root(40^2+80^2) - 12 years agoHelpfull: Yes(13) No(10)
- Distnace between House and T junction = 20 x 2 = 40.
ie., B reached T at 11 am.
B continued to right after 11 am and travelled upto 2. So distance covered by him = 3 x 40 = 120
A reached T at 12 noon and travelled upto 2 So distanced travelled by him = 2 x 20 = 40
So total distance between them = 120 + 40 = 160 km - 9 years agoHelpfull: Yes(9) No(0)
- data missing or dummy question
- 12 years agoHelpfull: Yes(7) No(17)
- Kajal Sharma:
it is T shaped junction.so, no any way to go straight. - 12 years agoHelpfull: Yes(4) No(4)
- distance between them is 120 +40=160 km
know one goes straight t junction they r going oposite direction - 9 years agoHelpfull: Yes(4) No(0)
- at 2 pm. a would be 40 km from the junction, and b would be 120 kms from junction as said by @ SHANU JAIN
but distance between them should be 120-40=80 kms as both are travelling in same direction - 12 years agoHelpfull: Yes(1) No(3)
- sqt((40^2)+(80^2)) is ans
- 12 years agoHelpfull: Yes(1) No(1)
- let H be starting point and T ending point
after 2 hrs A reaches T ie distance = 20*2=40km(H to T)
we can crosscheck this as b takes 40km/hr to reach T and offcourse earlier than a.
again at 2 pm both reaches at another point say Q in another 2 hours
therefore b takes 2 hours more to reach Q
therefore distance between H and Q is 40*3=120km - 9 years agoHelpfull: Yes(1) No(0)
- here what abt dirn
- 9 years agoHelpfull: Yes(1) No(0)
- the speed of a=20kmph
the speed of b=40kmph
they meet at t junctin with in 2 hrs means
distanc by a=20/2=10
distance by b=40/2=20
so total distance=30
so at 2'o clk the distance bvn them is=30 - 12 years agoHelpfull: Yes(0) No(13)
- i agree wid kajal
- 12 years agoHelpfull: Yes(0) No(4)
- ldng(eai) cons and vowels are seperated...tot 5 lr ie)5!=120. then vowel can take the form of 3!=6... multi 120*6=720
- 12 years agoHelpfull: Yes(0) No(5)
- start by "a"(10 am)
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.40 km{by "a"
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.(t)meet both{"a" and"b")(at 12 am "b " move right).....80 kmy "b"..at 2 pm..end
.a go down
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.40 km by "a"at 2 pm end
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.80km by "b"
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.start by "b"{10 am)[
[simply 40^2+80^2=total distance - 12 years agoHelpfull: Yes(0) No(4)
- kajal is right...ans should be sqrt(80^2+40^2).
- 12 years agoHelpfull: Yes(0) No(6)
- kajal sharma is right i think.
- 12 years agoHelpfull: Yes(0) No(4)
- a travels 40 kms at 12pm
b travels juntion t at 11am thats he travels 40kms
and turns write travels 120 kms till 2 pm
a travels 40 kms at 2 pm
by pithogorous theorem sqrt(120^2+40^2)=126.49kms - 12 years agoHelpfull: Yes(0) No(4)
- as b has already travelld 40 km earlier so 120+40=160
- 10 years agoHelpfull: Yes(0) No(1)
- you r wrong abhishek.....
- 10 years agoHelpfull: Yes(0) No(1)
- how can we say that B is reached at 11 am????????
- 9 years agoHelpfull: Yes(0) No(0)
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