Mother daughter infant age is 74 Mother age is 46 more then daughter and infant And infant age is 0

m+d+i=74
m=46+d+i
I=.4d
m+1.4d=74
m-1.4d=46
m=60
d=10
I=4
10 years agoHelpfull: Yes(6) No(0)
M+D+I=74,
M=46+D+I
I=0.4D
M=46+D+0.4D
46+D+0.4D+D+0.4D=74
46+2D+0.8D=74
74-46=2.8D
28=2.8D
D=10
DAUGHTER AGE IS 10
10 years agoHelpfull: Yes(5) No(0)
m=46+d+i
i=0.4*d
m+i+d= 74
Solve all
d = 10 yrs
10 years agoHelpfull: Yes(2) No(0)
answer is 20
46+x+0.4x = 74 solve this. you get the answer as 20. Infant age is=8
10 years agoHelpfull: Yes(0) No(4)
if daughters age is x , then infants age is 0.4x
then, x + 0.4x + 46 = 74
x = (74 - 46) / 1.4
x = 20
so the age of daughter is 20
9 years agoHelpfull: Yes(0) No(2)
let d be daughter age
infant age=0.4
mother age=(d+0.4d)+46
therefore (d+0.4d)+46+d+0.4d=74
2.8d=28
d=10 year
8 years agoHelpfull: Yes(0) No(0)

Mother + daughter + infant age is 74. Mother age is 46 more then daughter and infant.
And infant age is 0.4 of daughter. Find daughters age.