how many integer values of x can satisfy the eq x 2

-2,-1,0,2 these integer values will satisfy the equation.
Option A. 4
9 years agoHelpfull: Yes(3) No(0)
the answer is option (b) 2 only two solutions are possible -1 and 2
9 years agoHelpfull: Yes(2) No(0)
Answer : 3
9 years agoHelpfull: Yes(1) No(2)
3. taking log both sides, either x+2=0 or x^2-x-1=1
9 years agoHelpfull: Yes(1) No(0)
o always a trivial solutn of polynomial
9 years agoHelpfull: Yes(1) No(0)
answer is 2
9 years agoHelpfull: Yes(0) No(3)
-1,-2,0,1,2....
ans: d
9 years agoHelpfull: Yes(0) No(1)
please explain this
9 years agoHelpfull: Yes(0) No(1)
taking log both sides we have
either x+2 =0 which gives x=-2
else log (x^2-x-1)=0 which results in x=2,-1
9 years agoHelpfull: Yes(0) No(1)
2 WILL SATISFY
9 years agoHelpfull: Yes(0) No(2)
let a=>a^0=1
=>let a= x^2-x-1
then a^(x+2)=1
=>x+2=0 =>x=-2 so ans is d)none of these
9 years agoHelpfull: Yes(0) No(1)
sub x=0,-1,2,-2 in the given eqn
ans is 4
9 years agoHelpfull: Yes(0) No(0)
d) none of these.

-2,-1,0,1,2 i.e 5 integers satisfies the equation. maybe even more integers as well.
9 years agoHelpfull: Yes(0) No(0)

how many integer values of x can satisfy the eq : (x^2 - x -1)^(x+2)=1
a 4 b 2 c 3 d none of these