jake runs faster than paul.jake and paul each walk 24kms.the sum of the speeds is 7km/hr and the sum of the time taken by them is hrs.then jake's speed is?

• jake runs faster than paul.jake and paul each walk 24kms.the sum of the speeds is 7km/hr and the sum of the time taken by them is 14 hrs.then jake's speed is?
• 12 years agoHelpfull: Yes(16) No(5)
• then go by option . the options are a)7kmph b)3kmph c)5 kmph d) 4 kmph
  j+p=7
  
  take option b)5:2 .... (24/5+24/2)not equal to 14
  take option c)4:3......(24/4+24/3)=14 hrs
  so the ans is 4:3
• 11 years agoHelpfull: Yes(16) No(6)
• question is complete..!!
  sol: 24/7-j + 24/j =14
  here j is jack speed n 7-j is paul
  on solving we get a eqn
  14j^2-98j+168=0
  solving we get j=4 n 3
  but jack is faster hence ans is 4 km/hr..!!
• 11 years agoHelpfull: Yes(11) No(1)
• incomplete question...
• 12 years agoHelpfull: Yes(6) No(5)
• speed be x ,7-x hence sum of speed is given.
  t1 =24/x t2 =24/7-x =14 sum of time given.
  solving we get7x-x^2=12.
  x=3,4
  since jake runs faster hence answer is 4.
• 10 years agoHelpfull: Yes(6) No(1)
• how many hrs????
• 12 years agoHelpfull: Yes(2) No(4)
• sum of speed=7 km/hr
  total time taken=14 hrs.
  distance=24 km.
  jake+paul=7km/hr.
  time=distance/speed
  assume from options given.
  14=(24/4)+(24/3)
  14=6+8.
  there fore speed of jake is 4.
  reason for 4 is :just assume the answer from the option and compare it ,because 24 is divisible by 4 and 3from the option
• 9 years agoHelpfull: Yes(1) No(0)
• (d/t1+d/t2)=7....(1)
  t1+t2=14......(2)
  from eq 1
  t1*t2=48(d=24)
  t1-t2=sqrt((t1+t2)^2-4*t1*t2)....(3)
  solve eq 1 and eq 3
  we get t2 and t1 value
  after that speed of jack is d/t2
  24/6=4kmph
  
  
• 10 years agoHelpfull: Yes(0) No(2)
• incomplete solution sum of the time taken is not given
• 10 years agoHelpfull: Yes(0) No(4)
• it think jake speed is 4 km/h
  24/4+24/3=14
  so jake is 4
  
• 9 years agoHelpfull: Yes(0) No(1)