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Numerical Ability
Profit and Loss
a cow and a horse are bought for rs200000.the cow is sold at profit of 20% and the horse at a loss of 10%.the overall gaim is 4000rs.the cost price of cow is
Read Solution (Total 8)
-
- Let, the cost price of cow be c and that of horse be h.
Then,
c+h=200000
Selling price of Cow & Horse = 6c/5 + 9h/10
=(12c + 9h)/10
now, (12c + 9h)/10=204000
12c+9h =2040000 .....eq 1
12c+12h=2400000 .....eq 2
3h=360000
=> h= Rs.120000
c=200000-120000
=80000
Cost of cow = Rs. 80000
Cost of Horse=Rs. 36000
- 12 years agoHelpfull: Yes(25) No(7)
- c.p(cow)=c;
c.p(horse)=h;
c+h=200000; (equation 1)
s.p(cow)=120c/100=1.2c;
s.p(horse)=90h/100=.9h;
gain=total s.p-total c.p = (1.2c+.9h)-(c+h)=4000 (given)
.2c-.1h=4000 (equation 2)
solve eq 1 & 2
c=80000 - 12 years agoHelpfull: Yes(17) No(2)
- let the c.p of cow =rs x
c.p of horse=rs 200000-x
ATP
20%0f x-10%of(200000-x)=4000
x=rs 80000 ans. - 9 years agoHelpfull: Yes(8) No(3)
- ans is 8000
- 12 years agoHelpfull: Yes(5) No(6)
- Using Allegation we can solve this question.
Percentage gain on the whole transaction =(4000/200000)*100 %
=2%
cow horse
+20% -10%
/
2%
/
(2-(-10))% (20-2)%
12% 18%
so, cow:horse=12:18=2:3
so cost price of cow =(2/5)*200000=80000 - 9 years agoHelpfull: Yes(5) No(0)
- c.p(h)=200000
c.p(c)=x
total profit = .2*x -.1*200000
=.2x-20000
it is given to be rs 4000
.2x-20000 = 4000
.2x=24000
x=120000 - 12 years agoHelpfull: Yes(4) No(1)
- they asked me also the same ques but i cudnt ans it....
- 12 years agoHelpfull: Yes(2) No(2)
- answer is 8000
- 5 years agoHelpfull: Yes(0) No(0)
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