x completes (1/3)rd of the work in 4 days, y completes (1/6)th of the work in 3days, z completes (1/2) of the work in 5 days. If x,y,z work for 3 days and then x,z left, how many days will y take to complete the remaining work?

• x complete work in 12days
  y complete work in 18days
  z complete work in 10days
  together they work for 3 days ie 43/180 work complete
  nw x,z left
  therefore 43*3/180+x/18=1
  hence x=51/10days
• 12 years agoHelpfull: Yes(30) No(1)
• x's 1 day work=1/12
  y's=1/18
  z's=1/10
  now work done by all(x+y+z) in one day =1/12+1/18+1/10=43/180
  work done by all(x+y+z) in 3 days=3*43/180=43/60
  remaining work=1-43/60=17/60
  therefore no. of day required by y alone=18*17/60=5.1 days
  
• 12 years agoHelpfull: Yes(6) No(0)
• x's 1 day work=1/12
  y's=1/18
  z's=1/10
  now x+y+z=43/180
  remaining work 1-(43/180)
  =137/180
  time taken by y will be= (137/180)*18=aprrox 14
• 12 years agoHelpfull: Yes(2) No(6)