If the sum of reciprocals of two numbers is 1/12 then what are the numbers.

• let number be a & b
  
  then (1/a)+(1/b)=(1/12)
  (1/a) = (1/12)-(1/b)
  a = 12b/(b-12)
  
  if b=13 then a=156
  if b=1 then a = -(12/11)
  if b=3 then a= -4
  and so on
• 12 years agoHelpfull: Yes(6) No(0)
• it shud b mentioned that the two intigers should b consecutive to each odr
  
• 12 years agoHelpfull: Yes(3) No(0)
• 3 n 4
  1 / x + 1 / (x + 1) = 7 / 12
  (x + 1 + x) / (x(x + 1)) = 7 / 12
  12(2x + 1) = 7x(x + 1)
  24x + 12 = 7x² + 7x
  7x² – 17x - 12 = 0
  (x – 3)(x + 4 / 7) = 0
  x = 3, – 4 / 7
  
• 12 years agoHelpfull: Yes(2) No(5)
• 1 / x + 1 / (x + 1) = 7 / 12
  (x + 1 + x) / (x(x + 1)) = 7 / 12
  12(2x + 1) = 7x(x + 1)
  24x + 12 = 7x² + 7x
  7x² – 17x - 12 = 0
  (x – 3)(x + 4 / 7) = 0
  x = 3, – 4 / 7
  
  – 4 / 7 is not an integer, so we discard this solution.
  
  If the smaller integer is 3, then the second must be 3 + 1 = 4
  
  Answer: 3, 4.
• 12 years agoHelpfull: Yes(1) No(6)