if J finishes a work in 16days, P finishes a work in 24days, J,P,H together finishes in 8 days, Then in how many days will H complete the work alone?

• given j finish work in 16 so in one day=1/16
  p...................in 24..............=1/24
  according to question j+p+h=1/8
  then h=1/8-(j+p)
  h=1/8-(1/16+1/24)
  h=48
• 11 years agoHelpfull: Yes(17) No(0)
• let H takes x days
  So, 1/x+ 1/16 + 1/24 = 1/8
  =>1/x + 5/48 = 1/8
  =>1/x = 1/8-5/48 = 1/48
  => x=48 days
  
• 11 years agoHelpfull: Yes(6) No(0)
• easy way to do this type of questions in competitive exam in less time is
  take lcm of all
  lcm of 16,24 and 8 is 48
  so j finish 48/16=3 units
  so p finish 48/24=2 units
  J,P,H together finishes 48/8=6 units
  so h will finish 6-(3+2)=1 units
  so h will finish work in 48*1=48 days(ans)
  
• 11 years agoHelpfull: Yes(5) No(0)
• 48days......
• 11 years agoHelpfull: Yes(3) No(0)
• j in 1 day=1/16;
  p in 1 day=1/24;
  (j+p+h)=1/8;---(1);
  from equation 1 we get h=1/48;
  so,j complete the whole work in (1/(1/48))=48 days.
• 11 years agoHelpfull: Yes(1) No(0)
• forty eight
• 11 years agoHelpfull: Yes(1) No(0)
• j+p+h=1/8
  j=1/16
  p=1/24
  h=1/8-1/16-1/24=1/48
  
• 11 years agoHelpfull: Yes(1) No(0)