Ram and Shakil run a race of 2000m. First Ram gives Shakil a start of 200m and beats him by 1 minute.Next Ram gives shakil a start of 6 min and is beaten by 1000 meters . Find the time in minutes in which Ram and Shakil can run the race seperately.
a)12.18
b)10.18
c)10.12
d)8.10

• let speed of ram and shakil be x and y resp.
  case1: ram gives a start of 200m and beats shakil by 1 minute.
  
  2000/x - 1800/y= -60
  2000/x= 1800/y -60---------------------(1)
  
  case2: ram gives shakil a start of 6 min and is beaten by 1000 meters
  
  distance travelled by shakil in 6 minutes= (6*60*y) meters = 360y meters
  
  1000/x = (2000- 360y)/y------------------(2)
  
  solve for x, y..
  
  answer is x=8minutes, y= 10minutes
• 9 years agoHelpfull: Yes(8) No(0)
• LET r be velocity of ram and s be the velocity of Shakil then (2000/r)=(1800/s)-60......(1)
  second case distance Shakil travel in 6 min=360s
  again equating time for both 1000/r=(2000-360s)/s.......(2)
  solving (1) &(2) we get
  s=20/6
  putting value in first we get time =480sec=8min
• 9 years agoHelpfull: Yes(0) No(0)