2 vertical poles of height 2 mt and 8 mt stand apart on a plane. the height in mt of their point of intersection of the top of each poles to bottom of other pole is
a)1.6
b)5.8
c)1.8
d)cant be determined

• (x*y)/(x=y)
  (2*8)/(2+8)
  =16/10=1.6
• 9 years agoHelpfull: Yes(6) No(0)
• Let us call that height x; the horizontal distance form this intersection point to the 2 m pole a; and the horizontal distance to the 8 m pole b. Just skecth it on paper and notice the similarity of triangles, such that:
  (a+b)/2 = b/x , and
  (a+b)/8 = a/x
  Now, if we add both sides:
  5(a+b)/8 = (a+b)/x
  Hence, x=8/5=1.6m.
• 9 years agoHelpfull: Yes(1) No(0)
• 1.6.....using the concepts of similarity of triangles that if the triangles are similar then their sides are proportional...
  x/2=b/(a+b)
  =>(a+b)/2=b/x............(1)
  x/8=a/(a+b)
  =>(a+b)/8=a/x...........(2)
  adding (1) & (2) we get
  x=1.6 which is the height of their intersection of the top of each poles to bottom of other pole....
• 9 years agoHelpfull: Yes(0) No(0)