find the value for k so that the remainder for (x^3 + 2x^2 - kx + 5)divided by (x - 2) is 3.

• k=10
  In the second step of division,
  (8-k)x+5 / x-2 gives a remainder of 3,so the first first term has to be zero.
• 9 years agoHelpfull: Yes(0) No(0)
• k=9
  as by dividing by (x-2) the the remainder having k is=(8-k)x+5
  so to get remainder 3 dividing the (8-k)x+5 as quotient -1
  the value of k=9
• 9 years agoHelpfull: Yes(0) No(0)