If x^2+y+z=8 , y^2+z+x=6, z^2+x+y=12 ,then find x+y+x=?

• Ans=6.
  Exp=>
  putting x=2,the equations reduce to-
  y+z=4, y^2+z=4, z^2+y=10
  further we observe that selecting y=1 and z=3, satisfy the reduced equations,
  So we have x=2,y=1 and z=3 as a solution.
  Thus x+y+z=6 [Ans.]
  
  
  
• 12 years agoHelpfull: Yes(3) No(0)