A beaker contains 180 liters of alcohol. On 1st day, 60 l of alcohol is taken out and replaced by water. 2nd day, 60 l of mixture iss taken out and replaced by water and the process continues day after day. What will be the quantity of alcohol in beaker after 3 days

• 60 units taken everyday for 3day...
  therefore: [180(1-60/180)^3]=160/3 lit
• 9 years agoHelpfull: Yes(11) No(0)
• Final Alcohol = Initial Alcohol ×(1−Replacementquantity/FinalVolume)^n
  Final Alcohol = 180(1−60/180)^3 = 180×(23)3=53.3
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• ans is 53.33
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• 32
  1st day 60 al is taken out so now al=120l nd water=60 so ration of mixture is 120:60=2:1
  Next day again 60 l so al taken out =60*2/3=40 now new ratio = 80:100=4:5
  Same third day 60*4/5=48 ltr so now total amount of alcohol in mixture is 80-48 =32
• 9 years agoHelpfull: Yes(0) No(4)