find the no. of polynomial for degree of x>+1 where f(x2)=f(x)2=f(f(x))

• only 1 possible. x^2
• 12 years agoHelpfull: Yes(6) No(4)
• x^2 satisfies the equation.
  as f(x^2)=f(x)^2=f(f(x))
  now if we put f(x)=x^2 then
  f(x^2)=(x^2)^2=x^4
  f(x)^2=(x^2)^2=X^4
  f(f(x))=f(x^2)=x^4
  
  if we put f(x)=x^3 then
  f(x^2)=(x^3)^2=x^6
  f(x)^2=(x^3)^2=X^6
  f(f(x))=f(x^3)=x^3=9
  
  so from degree 3 onwards the equation doesn't satisfy.
  
• 12 years agoHelpfull: Yes(3) No(0)
• only 1...............
• 12 years agoHelpfull: Yes(2) No(0)