how many four digit number can be formed with 12345 that r divisible by 4 and digits r not repeated

• ans 24
  last 2 digit should be 12 32 52 24
  so 3P2*4=24
• 12 years agoHelpfull: Yes(39) No(2)
• ANS 30
  last 2 digits should be 12 16 24 32 52
  so 3c1*2c1*5 ==30
• 12 years agoHelpfull: Yes(4) No(28)
• possibilities for last two digits are 12,24,52,24, for the first two digits we can select from remaing three digits i.e 3c2 =6
  6*4 =24
• 12 years agoHelpfull: Yes(4) No(2)
• answer is 30 ....plzz read the question carefully repetation z not allowed ...so last two digit may be 12 24 32 44 52 ....so first three digit now select in 6 ways ..so tatal ways is 30 .....if repetation z allowed then it will bwcamee..125 ways ..
• 12 years agoHelpfull: Yes(4) No(1)
• no.s to be divided shud hv 12 32 24 or 52 in d last two places nd in the first two places 3 no.s hv to be arranged dt cud b arranged dat could b arranged in 6 ways so
  6*4= 24 ans
  
• 12 years agoHelpfull: Yes(3) No(3)
• last 2 digits divisible by 4 are 12,32,44,52,24 and remaining 2 digits can be arranged in 5^2 ways as repetition is permitted. so answer is 5^2*5=5^3.
  so ans is 125.
• 12 years agoHelpfull: Yes(2) No(2)
• sorry that for 9 digit.
  for 4 digit divisible by 4 will be
  12,24,32,42,52 is last digit and remaning placess 5^2*5=5^3 is exact answer
• 12 years agoHelpfull: Yes(1) No(14)
• tito i think we can not count 16 bcoz it we hv to form using 1,2,3,4,5 only.
• 12 years agoHelpfull: Yes(1) No(4)
• we have to form 4 digit no.
  _ _ 12
  _ _ 24
  _ _ 32
  _ _ 44
  _ _ 52
  so we have 5 ways of last two digits n remaining 2 digit space left that can be done in 5^2 ways.so total 5*5^2=5^3 is answer
• 12 years agoHelpfull: Yes(1) No(5)
• last 2 digit must be divisible by 4 so 12,24,32,42,52 and remain places is 5^7
  so total number is 5^8
• 12 years agoHelpfull: Yes(0) No(6)
• ANS 24
  last 2 digits should be 12 24 32 52
  so 3c1*2c1*4 ==24
• 12 years agoHelpfull: Yes(0) No(2)
• last 2 digits should be 12,24,32
  so remaining 2 digit can be fill by 3&2 ways
  so( 2*3)*3=18
• 12 years agoHelpfull: Yes(0) No(2)
• sorry for the previous solution.
  the answer is 3C1*2C1*4=24
  as the number divisible by 4 ends with 12,32,52,24
  and the first two digits are combination of the remaining 3 and 2 digits as repeatation is not allowed.
• 12 years agoHelpfull: Yes(0) No(1)
• but shouldnt it be (3^2)*4 as we can select 2 numbers from the remaining 3 numbers left.?
• 12 years agoHelpfull: Yes(0) No(0)