In a mixture of a, b and c, if a and b are mixed in 3:5 ratio and b and c are mixed in 8:5 ratio and if the final mixture is 35 liters, find the amount of b?

• here a/b=3/5
  b/c=8/5
  
  
  a/b changed as (24/5)/8
  b/c =8/5
  
  then a:b:c=24:40:25
  
  then the amount of b=(35*40)/89=15.7 liters
  
• 9 years agoHelpfull: Yes(5) No(1)
• here a/b=3/5 and b/c=8/5
  and given a+b+c=35
  first we have to equal b in both the ratios
  so multiplying numerator and denominator of a/b by 8 and for b/c by 5 we have
  a/b=24/40 and b/c=40/25
  now b is equal.
  let a=24x,b=40x,c=25x
  since a+b+c=35
  ->24x+40x+25x=35
  ->x=.39 (approx)
  therefore b= 40 *x=40*.39=15.6 ans
• 9 years agoHelpfull: Yes(5) No(1)
• a:b=3:5
  b:c=8:5
  now a=3*8
  a=24
  
  b=5*8
  b=40
  
  c=5*5
  c=25
  total of abs =(24+40+25)=89
  Final mixture=35 liters
  then b liters=(40*35)/89
  
  b=1400/89
  b=15.73 Ans
  
  
• 9 years agoHelpfull: Yes(1) No(0)
• 15.7liters
• 9 years agoHelpfull: Yes(0) No(0)
• a:b =3:5
  b:c=8:5
  a:b:c:=24:40:15
  so b'share is 35*40/79=
  17.721
• 9 years agoHelpfull: Yes(0) No(3)
• here a/b=3/5
  b/c=8/5
  
  
  a/b changed as (24/5)/8
  b/c =8/5
  
  then a:b:c=24:40:25
  
  then the amount of b=(35*40)/89=15.7 liters
• 5 years agoHelpfull: Yes(0) No(0)