pqr is a three digit natural number so that pqr=p!+q!+r!.what is the value of(q+r)p

• ANS IS 9
  I.E 145=1!+4!+5!=1+24+120
  P=1,Q=4, R=5
  (Q+R)P=(4+5)1=9
  
• 11 years agoHelpfull: Yes(18) No(1)
• As 7! is 5040 therefore p,q,r < 7 as given pqr is three digit number.
  Also P > 0 as pqr is three digit number.
  
  Case1) if p= 6,then 6qr=6!+q!+r!=720+q!+r! Which is not possible as LHS700.
  Therefore p is not 6.
  
  Case2) if p= 5,then 5qr=5!+q!+r!=120+q!+r!
  Now if q or r is 6 then 5qr is not equal to 120+q!+r!
  As 6!=720 which makes LHS
• 7 years agoHelpfull: Yes(3) No(0)
• ans:-9
  the number is 145 got it by trial and error
• 11 years agoHelpfull: Yes(2) No(2)
• 145 is pieterson no. so required ans is 9
• 11 years agoHelpfull: Yes(2) No(2)
• ans:-9
  pqr=145
  p(q+r)=1(4+5)=9
• 11 years agoHelpfull: Yes(2) No(0)
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• 11 years agoHelpfull: Yes(0) No(3)
• ans) p=1,q=4,r=5. (5+4)1=9ans
  
• 11 years agoHelpfull: Yes(0) No(0)
• I have posted complete solution BT there is no complete solution on display box.why?
• 7 years agoHelpfull: Yes(0) No(0)