A and B throw a dice. The probabilty that A's throw is not greater than B's is
(a) 5/12
(b) 7/12
(c) 11/12
(d) 5/36

• possibilities are
  (1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
  (2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
  (3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
  (4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
  (5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
  (6,1),(6,2),(6,3),(6,4),(6,5),(6,6)
  favourables=
  {(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),
  (2,2),(2,3),(2,4),(2,5),(2,6),
  (3,3),(3,4),(3,5),(3,6),
  (4,4),(4,5),(4,6),
  (5,5),(5,6),
  (6,6)}
  No.=6+5+4+3+2+1=21
  Probability=21/36
• 11 years agoHelpfull: Yes(12) No(0)
• ans is b i.e 7/12
  if b's outcome is 6, a's outcome can be 6,5,4,3,2,1.total=6
  similarly if b's outcome is 5,a's outcome can be 5,4,3,2,1=5
  so a's outcome which is lower then b is 6+5+4+3+2+1=21
  and total outcome is 36 so our probability is 21/36 or 7/12
• 11 years agoHelpfull: Yes(9) No(0)
• require set ={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,2),(2,3),(2,4),(2,5),(2,6),(3,3),(3,4),(3,5),(3,6),(4,4),(4,5),(4,6),(5,5),(5,6),(6,6)}=21
  so,p(A!>B)=21/36=7/12
• 11 years agoHelpfull: Yes(4) No(0)
• no of out comes when we throw 2 dice is 36
  and the required out comes are 21
  so p(A!>B)=21/36=7/12
• 11 years agoHelpfull: Yes(1) No(0)