In 4 years, Rajs father will be double Rajs age then. Two years ago, while his mother was twice his age that time. If Raj is going to be 32 years old 8 years from now, then what is the sum of his parents age now?

• R.F=RAJS FATHER AGE
  R=RAJS AGE
  R.M=RAJS MOTHER AGE
  (R.F+4)=2*(R+4)
  (R.M-2)=2*(R-2)
  R+8=32
  therefore, R=24
  therefore, R.M=46
  therefore, R.F=52
  R.F + R.M = 98
• 9 years agoHelpfull: Yes(41) No(5)
• 98 year is ans
• 9 years agoHelpfull: Yes(5) No(7)
• if raj's present age is x
  then fathers age after 4 yr=2(x+4)
  mothers age 2 yrs ago =2(x-2)
  and x+8=32
  x=24
  so fathers age=52
  mothers age=46
  total=98
  
• 9 years agoHelpfull: Yes(3) No(2)
• Let,
  Raj's age be x
  Mother and father's age be y and z respectively
  2(x-2)=z
  2(x+4)=y
  x+8=32
  x=24
  solving above equations...
  Y+Z=100
• 9 years agoHelpfull: Yes(3) No(1)
• 52 is the father's age and 46 is the mother's age.So 98 will be the sum
• 9 years agoHelpfull: Yes(2) No(0)
• 2(R+4)=(F+4)
  2(R-2)=M-2
  R+8=32
  solving all we get 98
• 9 years agoHelpfull: Yes(2) No(1)
• ans is 100
  rajs age, r=32
  before 8 years rajs age is (32-8) i,e.,24
  rajs father age = r.f
  after 4years, r.f= 2*(r+4) = 2*(24+4) = 56
  rajs mother age=r.m
  before 2 years, r.m=2*(r-2) = 2*(24-2) = 44
  r.f + r.m = 100
• 9 years agoHelpfull: Yes(0) No(3)
• ans is 98
  
• 9 years agoHelpfull: Yes(0) No(0)
• let present ages of raj his father and his mother be x,y and z respectively.
  then (y+1)=2(x+4)...........(1)
  (z-2)=2(x-2).............(2)
  x+8=32........(3)
  solving all three equations we get x=24 y=55 and z=46. so sum of his parents age=y+z=101
• 9 years agoHelpfull: Yes(0) No(1)
• after 8 years raj age is 32 so present age of raj is 24. according to question after 4 year raj age is 28 so father age is 56 and from 2nd part of question 2years ago raha age is 22 so mother age is 44 . so present mother is 46 and fathers age is 52 so sum of the age is 98
• 9 years agoHelpfull: Yes(0) No(1)
• R.F=RAJS FATHER AGE
  R=RAJS AGE
  R.M=RAJS MOTHER AGE
  
  Raj age after 8 yrs 32
  so 32-8 = 24 (8 yrs back from now)
  
  Again, raj 24 + 4yrs =28 ( 4 yrs back from now)
  that time R.F was 28*2= 56 (double of raj)
  and R.M 2 yrs ago when raj was 24 she was ((24-2)*2)=44
  
  now after 8 years R.F will be 56+4=60
  and R.M will be 44+10=54 as 10 yrs back she was 44 from now
  60+54 = 114
• 9 years agoHelpfull: Yes(0) No(2)
• lets take father age=f,son=r,mother=m
  after 4 years f+4=2(r+4)
  before 2 years r-2=2(m-2)
  after 4 years r+8=32->r=24
  substitute r=24 in eqn 1 and 2
  you will get f=52,m=46
  f+m=98
  
• 9 years agoHelpfull: Yes(0) No(0)
• answer is 100. it is given his current age is 32-8=24.
  fathers age after four years will be twice his age. so father's age=(24+4)*2=56
  mother's age was twice raj's age two years ago then mother's age=(24-2)*2=44
  sum of parents age= 56+44=100
• 9 years agoHelpfull: Yes(0) No(2)
• Raj's present age=32-8=24.
  Two years ago, his mother age=2*his age at that time=2*22=44.
  therefore,his mother's age at present=44+2=46.
  four years later, his father age=2*his age at that time=2*28=56.
  therefore,his father's age at present=56-4=52.
  hence, the sum of his parents age now is=46+52=98.
• 4 years agoHelpfull: Yes(0) No(0)
• Rf + 4 = 2(R+4) (1)
  Rm - 2 = 2(R-2) (2)
  after 8 years---
  R+8 = 32
  R = 24
  on putting value of R in 1 and 2 we get-
  Rf = 52, Rm = 46
  therefore sum, 52+46 = 98
• 4 years agoHelpfull: Yes(0) No(0)