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A solution of KMnO4 is reduced to MnO2 .The normality of solution is 0.6.
The molarity is
(a) 1.8M
(b) 0.6M
(c) 0.1M
(d) 0.2M
Read Solution (Total 2)
-
- oxidation state of Mn in KMno4=+7
oxidation state of Mn in Mno2=+4
Valency factor(VF)= change in oxidation state=7-4=3
Molarity*VF=Normality
=>Molarity= 0.6/3= 0.2M - 12 years agoHelpfull: Yes(6) No(0)
- n=4-1;
so,M=.6/3=0.2 - 12 years agoHelpfull: Yes(1) No(4)
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