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A solution of KMnO4 is reduced to MnO2 .The normality of solution is 0.6.
The molarity is
(a) 1.8M
(b) 0.6M
(c) 0.1M
(d) 0.2M

Read Solution (Total 2)

oxidation state of Mn in KMno4=+7
oxidation state of Mn in Mno2=+4
Valency factor(VF)= change in oxidation state=7-4=3
Molarity*VF=Normality
=>Molarity= 0.6/3= 0.2M
11 years agoHelpfull: Yes(6) No(0)

n=4-1;
so,M=.6/3=0.2
11 years agoHelpfull: Yes(1) No(4)

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