TCS Company Numerical Ability Sequence and Series

The sum of a series of numbers upto n terms is 1/n. Find the sum of all the numbers upto 2014
a) 1/20132014!
b)1/20132013!
c)2013!
d)2014!

Read Solution (Total 3)

1. 1/2013*2014!
9 years agoHelpfull: Yes(7) No(11)

please give explanations
8 years agoHelpfull: Yes(1) No(2)
Correct Question is :----

The sum of first n terms in a sequence is always 1/n.Find the product of the first 2014 terms (n! denotes the factorial of n,that is the product of the numbers(1,2……n))

a)-1/(2013!2013!)

b) 1/(2013!2013!)

c) 1/(2013!2014!)

d)- 1/(2013!2014!)
4 years agoHelpfull: Yes(0) No(2)

TCS Other Question

Total number 30,average of first 10 number is equal to average of last 20 digits ,then find out last 20 digits sum ? Find the summation of log(n), where n is a series of numbers from 1 to 1024. (Take the base of logarithm as 2).