101102103104105106..............149150. what is the remainder when divided by 9?

• ans 2
  explanation:
  sum of n numbers= n*(n+1)/2
  150*(150+1)/2= 11325
  100*(100+1)/2= 5050
  sum of numbers from 101 to 150 = 11325-5050 = 6275
  remainder when divide by 9 = rem(6275/9) = 2
  therefore 2 is the answer
• 9 years agoHelpfull: Yes(14) No(3)
• remainder is :- 2
  
• 9 years agoHelpfull: Yes(4) No(3)
• we can here apply arithmetic progression
  let us see
  101+102+103+-----------------------+149+150
  then we get sum of n terms will be 6275
  now when we divide 6275 by 9 we get 2 as remainder
  so ans will be remainder=2
• 9 years agoHelpfull: Yes(2) No(1)
• remainder=0
• 9 years agoHelpfull: Yes(1) No(2)
• I thhink it is 3
  
  
  n*(n+1)/2
  150*75=11235
  11325/9=3
• 9 years agoHelpfull: Yes(0) No(2)
• How it is 2
• 9 years agoHelpfull: Yes(0) No(1)
• sum of n numbers=n*(n+1)/2
  in given number n=450
  450*(450+1)/2=101475
  101475%9=0
• 9 years agoHelpfull: Yes(0) No(2)
• lets take sum of 1st 9 digit 101102103=9
  
  which is divisible by 9.
  
  lets take sum of 2nd consecutive 9 digits 104105106 =18
  
  which is divisible by 9.
  
  so last 6 digit remains then we can divide 149150 by 9 and remainder is 6.
  
  so Ans is 6
  
• 9 years agoHelpfull: Yes(0) No(1)
• 50 1's so = 50
  1 to 9 = 45
  10 to 19 = 1*10 +(1+2+3+.......+9)= 10+45=55
  20 to 29 =2*10 +( 1+2+.....9)= 20+45=65
  30 to 39 = 3*10 +( 1+2+3 .....9) =30 +45 =75
  40 to 49 = 4*10 +(1+2+3....9)=40+45 =85
  50 =5
  
  add=50+45+55+65+75+85+5=380/9 reminder is 2..
  
• 9 years agoHelpfull: Yes(0) No(0)
• ans 2..
  find out total of all the numbrs like.. 1+0+1+1+0+2+1+0+3+............+1+4+9+1+5+0
  u will get 380 and when it will be divided by 9 remainder comes out to be 2..
  
• 9 years agoHelpfull: Yes(0) No(0)