If alpha is a positive acute angle and 2sin alpha+15cos^2alpha=7,then the value of cot alpha is

• 2sin alpha+15cos^2alpha=7,
  2sin alpha+15(1-sin^2alpha)=7
  15 sin^2 alpha -2 sin alpha -8=0
  sin alpha= 4/5
  cos alpha= 3/5
  cot alpha = cos alpha/sin alpha= 3/4
• 12 years agoHelpfull: Yes(2) No(0)
• 3/4.2sinalpha+15cos^2alpha=7
  15sin^2apha-2sinalpha-8=0
  solving eqsn sinalpha=4/5
  cosalpha=3/5
  cotalpha=3/4
• 12 years agoHelpfull: Yes(1) No(0)