P is a point outside a circle and is 13cm away from its centre. A secant drawn from the point P intersects the circle at points A and B in such a way that PA=9cm and AB=7cm. the radius of the circle is

• Radius will be 5 cm.....
  Draw the figure and apply pythagoras theorem twice
• 11 years agoHelpfull: Yes(3) No(2)
• let another secant which passes from p and center
  let x and y are the intersect points
  it can be solve with a fundamental properties if circle's secant
  PA*PB=PX*PY
  9*13=(13-R)*(13+R)
  calculate it you will find R=5 cm
• 11 years agoHelpfull: Yes(3) No(1)