. If P(x) = ax4+bx3+cx2+dx+e has roots at x = 1, 2, 3, 4 and P(0) = 48, what is P(5)

• as x=1,2,3,4 are roots so (x-1)(x-2)(x-3)(x-4)will satisfy p(x) i.e
  K(x-1)(x-2)(x-3)(x-4)=ax4+bx3+cx2+dx+e=P(x)so put x=0 we get k*1*2*3*4=48 i.e k=2
  and now x=5 in same eqn p(5)=K(x-1)(x-2)(x-3)(x-4) i.e
  P(5)=2*4*3*2*1 => 48
• 11 years agoHelpfull: Yes(198) No(15)
• ans is 48 as the equation is independent of x
  put x=1 then px=a+b+c+d+e
  so ans is 48
• 11 years agoHelpfull: Yes(11) No(67)
• as x=1,2,3,4 are roots
  
  so (x-1)(x-2)(x-3)(x-4)will satisfy p(x)
  
  K(x-1)(x-2)(x-3)(x-4)=P(x)so put x=0
  
  we get k*1*2*3*4=48 i.e k=2
  
  and now x=5 in same eqn p(5)=K(x-1)(x-2)(x-3)(x-4) i.e
  
  P(5)=2*4*3*2*1 = 48
• 8 years agoHelpfull: Yes(8) No(1)
• SHIVAM i got the answer. Can you tel me this question come in which part of maths.
  I want to learn more related to this question more.
  
• 9 years agoHelpfull: Yes(5) No(6)
• range of constant function is singleton set
  f(x)=3; f(anything)=3;
  so p(5)=48
• 8 years agoHelpfull: Yes(1) No(4)
• please explain this problem in brief
  
• 7 years agoHelpfull: Yes(1) No(0)