the smallest number which when divided by 10, 15, 20, 35 leaves 6,11,16,31 as remainder is...

• (10-6)=(15-11)=(20-16)=(35-31)=4
  (lcm of 10,15,20,35)-4
  420-4=416(ans)
• 12 years agoHelpfull: Yes(43) No(1)
• 35*an odd integer +31
  the least odd integer satisfying is 11
  so ans is 35*11 + 31=416
  416
• 12 years agoHelpfull: Yes(8) No(1)
• ans is 836
• 12 years agoHelpfull: Yes(5) No(8)
• ans is 31+35=66
• 12 years agoHelpfull: Yes(3) No(17)
• indrajit u r right
• 12 years agoHelpfull: Yes(1) No(0)
• 836 is not right??? pls explain
• 12 years agoHelpfull: Yes(0) No(0)