when a no divided by 406 it gives 115 as a remainder when it divided by 29 what is the

let x is divided by 406 & gives quotient y & remainder 115 then

x = 406 * y + 115

now, x / 29 = (406 * y + 115)/29 = 406 * y/29 + 115/29

=> rem = 115/29 = 28
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28 is ans

Num is 406K+115
for diff value of K
406K+115 % 29 =28
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406k+115
=29*14k+29*3+28
remainder =28
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406+115=521
521/29=28(Ans)
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(406*k+115)/29 rmd =28
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Let the number be N.
So N = 406x + 115.
Now divide this number by 29. As 406 is exactly divisible by 29, we have to divide 115 by 29 and find the remainder. So remainder = 28
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x=406*291+115=118261
118261 mod 29=28(rem)
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answer is 28
9 years agoHelpfull: Yes(0) No(1)
28

28 is ans

Num is 406K+115

for diff value of K

406K+115 % 29 =28
9 years agoHelpfull: Yes(0) No(1)

when a no. divided by 406 it gives 115 as a remainder. when it divided by 29 what is the remainder.???