if 28a+30b+31c=365.
then a+b+c=?.a,b,c are natural numbers.

• a=1,b=4,c=7
  28 , 30 & 31 denotes the days in a month n 365 is the total no of days..
• 12 years agoHelpfull: Yes(21) No(0)
• there are 7 months of 31 days in a year
  & 4 months of 30 days in a year
  & 1 month of 28 days in a year
  so,
  1+4+7=12...i m sure
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• 28(1)+30(4)+31(7)=365
  a+b+c=1+4+7=12
• 12 years agoHelpfull: Yes(2) No(0)
• the three numbers represent the months having these many days,
  28(1)+30(4)+31(7)=365
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• a=4,b=3,c=2
  
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• sorry dat solution was wrng...
  d ans will be
  1,4,and 7 respectively...
• 12 years agoHelpfull: Yes(0) No(1)
• a = 28a- Feb month
  b = 31st - 6 month
  c = 30th- 5month
  
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• 12 is the ans
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• 28 a = consider as february,,it consists 28 days soooooo a=1
  30 b = april,june,spet,nov ,,,,,, it consists 30 days soooooo b=4
  31 c = jan,march,may,july,aug,oct,Dec ,,,,, it consists 31 days soooo c=7
  totaly,,( a+b+c)
  1+4+7=12
• 9 years agoHelpfull: Yes(0) No(0)