in a chess tornament 16 members played in tournament x and 20 played in tournament y
and 12 in both the tournaments,if each player played atleast one
of these tournaments,what is the total number of players?
a)24 b)36 c)32 d)48

• It should be a union b where a=16 and b=20
  So a (union) b=a+b-a(int)b
  =16+20-12=24
• 11 years agoHelpfull: Yes(6) No(2)
• aUb=a+b-aNb
  =16+20-12=24
• 11 years agoHelpfull: Yes(1) No(2)
• Atleast means one or more than one...ok??
  now from x no of players = 16
  and from y no of players= 20
  so due to atleast now more than one is also allowed so we will take that players also that belongs to both..so total no of players== 16+20+12=48 ans
  
• 11 years agoHelpfull: Yes(0) No(9)
• n(n-1) is sufficient ....y n(n-1)/2 is done..
  can any one explain it ?
• 10 years agoHelpfull: Yes(0) No(0)
• the answer is 48.
• 4 years agoHelpfull: Yes(0) No(0)