if CAT 72 GATE 99 then BODY a 120 b 128 c 138 d 184

CAT=3+1+20=24 now 24*3=7
GATE=7+1+20+5=33 now 33*3=99
BODY=2+15+4+25=46 now 46*3=138
12 years agoHelpfull: Yes(7) No(0)
CAT=(3+1+20)*3=72
GATE=(7+1+20+5)*3=99
BODY=(2+15+4+25)*3=46*3=138
so answer :c)138
12 years agoHelpfull: Yes(1) No(0)
ans: 138
a=1,b=2,c=3......z=26.
and CAT:
C=3,A=1,T=20
so CAT=3+1+20=24 and 24*3=72
like that GATE=7+1+20+5=33 and 33*3=99
now,
BODY=2+15+4+25=46 and 46*3=138

so answer is 138
12 years agoHelpfull: Yes(1) No(0)
ANS::-138
cat=72,(3+1+20)*3
gate=99,(7+1+20+5)*3
similarly BODY=(2+15+4+25)*3=138
12 years agoHelpfull: Yes(0) No(0)
c=3, a=1, t=20. 3+1+20=24. 24*3=72
same reason, b=2, o=15, d=4, y=25. 3*(2+15+4+25)=138
11 years agoHelpfull: Yes(0) No(0)
sum of the alphabet is multiple of 3
hence body = 46*3=138
5 years agoHelpfull: Yes(0) No(0)

if CAT=72 & GATE=99
then BODY=??
a)120
b)128
c)138
d)184