Four persons have to cross the bridge they are having one torch light Four persons take 1 2 5 10

ans:17 minute
Let A takes 1 min, B takes 2 min, C takes 5 min, D takes 10 min
1)first A and B will go (total 2 minute)
2)A will return (1 minute)
3)then C and D will go (10 minute)
4)then B will return (2 minute)
5)at last A and B will go(2 minute)
now add all minute to get total time
2+1+10+2+2=17 minute(ans)
11 years agoHelpfull: Yes(12) No(11)
for questions like these, time is always [(Time got by adding all 4) - 1]
i.e.

1 + 2 + 5 + 10 = 18 - 1 = 17 Ans
9 years agoHelpfull: Yes(10) No(3)
17 min.
a and b go= 2 min
a returns=1 min
c and d goes=10 min
b returns= 2 min
a and b goes=2 min
total=2+1+10+2+2=17
10 years agoHelpfull: Yes(6) No(2)
ans is 19 mins
at first 1 & 10 cross the bridge =>10min
1 is return & cross with 5 =>1+5min
...
totally=10+1+5+1+2
=>19mins..
11 years agoHelpfull: Yes(4) No(32)
first 10 n 1 goes-- so time is 10secs + return 1sec=11sec
next 5 n 1 goes-- so time is 5secs + return 1sec=6sec
finally 2 n 1 goes-- so time is 2secs=2sec
total 11+6+2=19sec
11 years agoHelpfull: Yes(1) No(10)
2+1+10+2+2=17 mins is right ANS
10 years agoHelpfull: Yes(1) No(2)
1 & 2 then 2 dropped, 1 came back
5 & 10 then both dropppped 2 came back
Now 1 & 2 will go
Total time 2 + 1 + 10 + 2 + 2 = 17
8 years agoHelpfull: Yes(1) No(0)
1 & 2 then 2 dropped, 1 came back
5 & 10 then both dropppped 2 came back
Now 1 & 2 will go
Total time 2 + 1 + 10 + 2 + 2 = 17
8 years agoHelpfull: Yes(1) No(0)

Four persons have to cross the bridge they are having one torch light. Four persons take 1,2,5,10 minutes respectively, when two persons are going the will take the time of the slowest person what is the time taken to cross all of them.