in how many ways 4 boys and 4 girls can sit alternately such that one particular boy B1 always sits with a particular girl G1

• 4 boys can be arranged in 4!
  now b1 sits with g1.....so there are remaining 3 slots
  where 3 girls can sit in 3!
  again there can be 2 arrangemnts where the 1st one is a girl or a boy
  so ans is 2*4!*3!=288
• 11 years agoHelpfull: Yes(40) No(1)
• consider B1 and G1 as one unit, now 4 boys can be placed in 4! ways. the remaining 3 girls are having 4 places to sit i.e 4C3 ways. and B1, G1 can be arranged in 2 ways. hence the ans is 4!*4!*2
• 11 years agoHelpfull: Yes(2) No(8)
• firstly arrange the boys and girls alternatively, so that the B1G1 B2 G2 B3 G3 B4 G4, here the B1G1 are considered as a single unit, so ans is 7!
• 11 years agoHelpfull: Yes(1) No(10)
• 48 ways.
  for b1g1 alone 6 combination.so for all 24.
  in the same way for g1b1 6 combinations posiible.totally 24+24=48
  
• 11 years agoHelpfull: Yes(1) No(2)
• 4 boys and 4 boys sit alternatel so
  _b1_b2_b3_b4_ this is the criterion
  so answer is=4!*5*4*3*2=2880
• 11 years agoHelpfull: Yes(0) No(8)
• indra jeet ur answer is partially correct... in the second last line u say..
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  "again there can be 2 arrangemnts where the 1st one is a girl or a boy"
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  which is wrong...since if u permutate the girl and the boy...then condition of alternate will fail..2 g will sit together in that case.....u can check that...so answer will be 144..not 288.... CHIAMAILLA
• 10 years agoHelpfull: Yes(0) No(0)