An event manager has ten patterns of chairs and eight patterns of tables. In how many ways can he make a pair of table and chair?

Option
1) 100
2) 80
3) 110
4) 64

• Answer is 2
  
  suppose ten pattern of chairs is A ,B,C,D,E,F,G,H,I,J.
  and eight pattern of table is 1.2.3.4.5.6.7,8
  
  then the pair look like this A1,A2,A3............A8=8
  and B1,B2,B3.............B8=8
  .
  .
  .
  .
  so on j1,j2,j3..............j8=8
  
  finally 8 * 10=80
  
  
  So Answer is 80
• 9 years agoHelpfull: Yes(8) No(0)
• = number of ways of choosing 1 pattern of chairs X number of ways of choosing 1 pattern of table
  = 10 X 8
  = 80
• 9 years agoHelpfull: Yes(1) No(0)
• Since there are 10 chairs and each chair have 8 options the number of ways in which they can be paired is 10 × 8 = 80.
• 6 years agoHelpfull: Yes(1) No(0)