the first 44 positive integers are written in order to form the largest number N=12345678910111213..424344. what will be the he remainder when N is diveded by 45?

• i am sorry..my prev ans was wrong..it will be like this
  no will be div by 45 when it is divided y both 9 and 5
  a no is div by 9 if sum of digits is div by 9
  now sum of digits of given no is 270
  so the no is div by 9
  and since last digit is 4 when div by 5 it leaves rem 4
  let us say numbers such as 9,54...
  we see they are div by 9 but leaves rem 4 when div by 5..
  so when div by 45 they leave rem 9
  so req ans=9
• 11 years agoHelpfull: Yes(20) No(12)
• no will be div by 45 when it is divided y both 9 and 5
  a no is div by 9 if sum of digits is div by 9
  now sum of digits of given no is 270
  so the no is div by 9
  and since last digit is 4 when div by 5 it leaves rem 4
  so req rem=4
• 11 years agoHelpfull: Yes(5) No(7)
• i cant get it how 270 came
  
  some one pls explain :(
• 11 years agoHelpfull: Yes(3) No(1)
• After adding the digits we get the no. divisible by 9 but it is not divisible by 45 as not divisible by 5.
  To make it divisible by 5 while keeping it divisible by 9 also, subtract 9 from the no.The resultant no. will have 35 in place of 44.So, the resultant no. is divisible by 45. Hence the original no. leaves remainder 9 when divided by 45.
• 11 years agoHelpfull: Yes(2) No(3)
• I want to give similar exampe for proper understanding, take 279
  If u add 2+7+9=18 which is divisible by 9 ,
  Now divided 279 by 5 ,u will get 4 as remainder ,
  Now divide the 279 by 45, u will get 9 as remainder (6*45=270), so remainder 9.
  Similarly, when the above number is divisible by 9 and leave remainder 4 then when it is divided by 45 it will give remainder as 9.
• 8 years agoHelpfull: Yes(1) No(1)
• N=1234......414344
  sum=270;
  IF N divided by 45,it should divided by 9 & 5.
  N is divisible by 9.
  
  9/9=1&1/5=>rem=1
  18/9=2&2/5=>rem=2
  27/9=3&3/5=>rem=3
  36/9=4&4/5=>rem=4
  45/9=5&5/5=>rem=0
  54/9=6&6/5=>rem=1
  63/9=7&7/5=>rem=2
  72/9=8&8/5=>rem=3
  81/9=9&9/5=>rem=4
  90/9=10&10/5=>rem=0
  ....so on..
  so, rem=(1,2,3,4,0 & again repeated)
  so rem is =4(according to option) (option is:4,9,14,18)
• 8 years agoHelpfull: Yes(1) No(3)
• how is it comming??plsssss xplain.
• 11 years agoHelpfull: Yes(0) No(5)
• 4 will be ans
• 11 years agoHelpfull: Yes(0) No(5)
• the sum of all digits are 310
  55+10+55+20+55+30+4+4+4+4+4+1+2+3+4=310
  310/9= reminder 4
  number - 4 = divsible by 9 nd 5
  so reminder is 4
• 11 years agoHelpfull: Yes(0) No(7)
• Ans=0
  when we sum up those integers the total =270 and it is divisible by 45.
  Note: 1st 9 digits sum=45
  then while summing 10 to 19 consider 10 as 1+0=1 and 1+9 as 10.so sum=55
  similarly for others
• 11 years agoHelpfull: Yes(0) No(4)
• Sorry i hurriy calculated .
  The sum =270
  And if 9 and 5 divides N then 45 will divide it.
  So 270 is divided by 9 .
  And when w divide it by 5 N will leave 4 as reminder(as last digit is 4).
  So ans=4
• 11 years agoHelpfull: Yes(0) No(3)
• Hi friends can anyone explain this briefly ?
  
• 8 years agoHelpfull: Yes(0) No(0)
• the sum of n numbers= n(n+1)/2 =44(45)/2=990
  990 divisible by 9
  also 45 divisible by 9
  hence denominator is 5... by the option 4 is only remainder of 5...therefore 4 is answer
• 4 years agoHelpfull: Yes(0) No(0)