3 cars A,B,C are in the race. A is twice as likely to win as B and B is thrice as likely to win as C. what is the probability that B will win,if only one can win the race.

• considering C=x
  then B=3x, A=6x
  probability of B will win is=3x
  total probability = 3x/(x+6x+3x)=3/10
  is this correct?
• 12 years agoHelpfull: Yes(28) No(2)
• 3/10
  
  a=2b
  b=3c
  a+b+c=1
  let c=k
  6k+3k+k=1
  k=1/10
  b=3/10
• 12 years agoHelpfull: Yes(3) No(2)
• if P(C)=1/x
  then,P(B)=3/x
  then,P(A)=6/x
  therefore probabilty of B winning is:
  P(B)/(P(A)+P(B)+P(C))
  replacing we get
  P(B)=3/10=0.3
• 12 years agoHelpfull: Yes(2) No(1)
• if P(C)=1/x
  then,P(B)=3/x
  then,P(A)=6/x
  therefore probabilty of B winning is:
  P(B)/(P(A)+P(B)+P(C))
  replacing we get
  P(B)=3/10=0.3
• 12 years agoHelpfull: Yes(1) No(2)
• sorry i forgot to give option and correct ans is 3/10
• 12 years agoHelpfull: Yes(1) No(1)
• A CHANCE TO WIN BE 2X
  B CHANCE TO WIN BE X
  C CHANCE TO WIN BE X/3
  PROB FOR B WIN=3/10
• 12 years agoHelpfull: Yes(1) No(2)
• 1/4 may be the ans yar option diya karo
• 12 years agoHelpfull: Yes(0) No(1)
• 3/10
  P(A)+P(B)+P(C)=1
  P(C)=1/x
  P(B)=3/x
  P(A)=6/x
  subst... P(B)=3/10
• 12 years agoHelpfull: Yes(0) No(1)
• ans is 3/10
  p(A)=2p(B)
  p(B)=3p(C)
  so,the prob of A is 6/10
  prob of B is 3/10
  prob of C is 1/10
  since the sample space is 10.
• 12 years agoHelpfull: Yes(0) No(1)
• a=2b,b=3c
  =>a=6c
  a:b:c=6:3:1
  prob that a wins= .6 =>fail prob =.4
  prob that b wins= .3 =>fail prob =.7
  prob that c wins= .1 =>fail prob =.9
  
  b wins and others fail
  therefore prob = .4*.3*.9=.108
  
  
  
• 12 years agoHelpfull: Yes(0) No(1)
• Let A=x, B=x/2, C=x/6
  A+B+C=1
  x=12/19
  so, P(B)=6/19
• 11 years agoHelpfull: Yes(0) No(0)