Q. In a group of 8 semifinalists, all but 2 will advance to the final round. if in the final round only top 3 will be awarded medals ,then how many groups of medal winners possible?

• It should be 8c3 or 56 , as the way of selecting from semifinals to finals and top 3 from semifinalists is not given. hence any 3 from the 8 could go to top 3 .
  so selecting 3 from 8 or 8c3
• 12 years agoHelpfull: Yes(31) No(9)
• Number of ways six semifinalists can be chosen = 8C6 = 28
  Number of ways three medal winners can be chosen = 6C3 = 20
  Total combination possible = 28* 20 = 560.
• 12 years agoHelpfull: Yes(19) No(5)
• possible no. of final round groups=8c2=28
  for each final group 3rd one will b from remaining 6,
  so, possible no. of 3rd one=6c1=6
  hence total no. of possible group of top three will b=28*6=168.
  
• 12 years agoHelpfull: Yes(6) No(4)
• The way to read the problem under discussion is that => from 8 it gets to 6 and from 6 it gets to 3. We will take the same flow for easy logic, hence it is 6 out of 8 (which is 8C6) and 3 out of 6 (which is 6C3) => totalling to 8C6*6C3 ways 560 is the ans
  
• 11 years agoHelpfull: Yes(6) No(1)
• Be careful here. The final round is immaterial. There are 8 contestants. Couldn't any one of these 8 be among the final 3 medal winners? All we need to determine is the the number of combinations of 3 that can be made from the 8 contestants:
  
  (8*7*6)/(1*2*3)=56
• 7 years agoHelpfull: Yes(2) No(0)
• 8c3=>> 8*7*6=336
• 10 years agoHelpfull: Yes(1) No(3)
• ccxfgdvj
  yes
  
• 12 years agoHelpfull: Yes(0) No(12)
• no. of groups are not defined
• 10 years agoHelpfull: Yes(0) No(2)
• 8C3 = 56 is Final.
• 4 years agoHelpfull: Yes(0) No(0)